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x^2-10x+5x+36=360
We move all terms to the left:
x^2-10x+5x+36-(360)=0
We add all the numbers together, and all the variables
x^2-5x-324=0
a = 1; b = -5; c = -324;
Δ = b2-4ac
Δ = -52-4·1·(-324)
Δ = 1321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1321}}{2*1}=\frac{5-\sqrt{1321}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1321}}{2*1}=\frac{5+\sqrt{1321}}{2} $
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